x^2-2x-3599=0

Solution for x^2-2x-3599=0 equation:

x^2-2x-3599=0

a = 1; b = -2; c = -3599;
Δ = b2-4ac
Δ = -22-4·1·(-3599)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-120}{2*1}=\frac{-118}{2}
=-59
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+120}{2*1}=\frac{122}{2}
=61
$